Question

7.3 Using appropriate identities, find the value of: a) (a+b)(a+b)*(a-b)(a-b)​

Answer 1

Answer:

2( b× a) is correct answer please Mark me brilliant

Answer 2

Suppose a + b = k & ab = n.

Suppose a + b = k & ab = n.So, b = k-a.

Suppose a + b = k & ab = n.So, b = k-a.Putting b = (k-a) in ab = n,

Suppose a + b = k & ab = n.So, b = k-a.Putting b = (k-a) in ab = n,a (k-a) = n.

Suppose a + b = k & ab = n.So, b = k-a.Putting b = (k-a) in ab = n,a (k-a) = n.ka - a^2 - n =-0.

Suppose a + b = k & ab = n.So, b = k-a.Putting b = (k-a) in ab = n,a (k-a) = n.ka - a^2 - n =-0.a^2 - ka + n = 0.

Suppose a + b = k & ab = n.So, b = k-a.Putting b = (k-a) in ab = n,a (k-a) = n.ka - a^2 - n =-0.a^2 - ka + n = 0.Use the quadratic formula to get the values of 'a' in terms of k & n. Put them in the original equation to get the values of b. You'll get 2 ordered pairs with values interchanged.

Suppose a + b = k & ab = n.So, b = k-a.Putting b = (k-a) in ab = n,a (k-a) = n.ka - a^2 - n =-0.a^2 - ka + n = 0.Use the quadratic formula to get the values of 'a' in terms of k & n. Put them in the original equation to get the values of b. You'll get 2 ordered pairs with values interchanged.E.g. a + b = 5 & ab = 6.

Suppose a + b = k & ab = n.So, b = k-a.Putting b = (k-a) in ab = n,a (k-a) = n.ka - a^2 - n =-0.a^2 - ka + n = 0.Use the quadratic formula to get the values of 'a' in terms of k & n. Put them in the original equation to get the values of b. You'll get 2 ordered pairs with values interchanged.E.g. a + b = 5 & ab = 6.If you solve it following this given procedure, you get :

Suppose a + b = k & ab = n.So, b = k-a.Putting b = (k-a) in ab = n,a (k-a) = n.ka - a^2 - n =-0.a^2 - ka + n = 0.Use the quadratic formula to get the values of 'a' in terms of k & n. Put them in the original equation to get the values of b. You'll get 2 ordered pairs with values interchanged.E.g. a + b = 5 & ab = 6.If you solve it following this given procedure, you get :(a,b) = (2,3), (3,2).