Question

7. ક્રમ માં કને આધારે સાબિત કરો કે આવર્ત કોષ્ટકના ચોથા આવર્તમાં 32 તત્વો હોવાં જોઈએ.
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Answer 1

Answer:

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In the modern periodic table , each period starts with the fillings of a new principal energy level . Thus the sixth period begins with the filling of principal quantum number n=6n=6 . When n=6,l =0 , 1,2,3 . But according to aufbau principle the electrons are added to different orbitals in order of their increasing energies . Now the energy of 6d- subshell is higher than that of 7s- subshell but energies of 5d- and 4f- subshells are lower than that of 6d- subshell . Therefore in 6th period electrons can be filled in only 6s- 4f, 5d and 6p- subshells whose energies increase in the order :6s<4f<5d<6p:6s<4f<5d<6p Now s- subshells has two p- subshell has three d- subshell has five and f- subshell has seven orbitals . Hence in all there are 16 (2+ 3 +5 + 7) orbitals that can be filled in this period. Since according to pauli's exclusions principle each orbital at the maximum can accommodate two elements therefore 16 orbitals at the d maximum can have 32 electrons and hence sixth period has 32 elements.

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