Math, asked by Abhinavbajaj9137, 10 months ago

√7(√35-√7)=p+q√5
Find the value p and q.

Answers

Answered by tahseen619
2

Answer:

p = - 7

q = 7

Step-by-step explanation:

Given:

 \sqrt{7} ( \sqrt{35}  -  \sqrt{7} ) = p + q \sqrt{5}

To find:

The value of p and q

Solution:

L.H.S

 \sqrt{7} ( \sqrt{35}  -  \sqrt{7} ) \\  \\  \sqrt{7  \times 7 \times 5}  -  \sqrt{7 \times  7}  \\  \\ 7 \sqrt{5}  - 7 \\  \\  - 7 + 7 \sqrt{5}

Comparing the L.H.S from R.H.S I get,

p = - 7

q√5 = 7√5

q = 7

Hence, the required value of p is -7 and q is 7 .

Answered by sudiplal22
2

Answer:

P = -7

Q = 7

Step-by-step explanation:

√7(√35-√7) = p+q√5

√7*√7(√5-1) = p+q√5

7√5-7 = p+q√5

p = -7

q = 7

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