Question

7.35 grams of a dibasuc acid was dissolved in water and diluted to 250 ml. 25 ml of this solution was neutralised by 15 ml , 1 N solution.Calculate equivalent weight and molecular weight of the acid​

Answer 1

Explanation:

n1v1=n2n2

so we get the normality of acid.

then we put the formula of normality.

my ans is 980gm.