Question

( 7/3p2 +4q 2 ) by 7(p2 − 4/3q2 )​

Answer 1

Step-by-step explanation:

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Answer 2

Given:

( 7/3p² +4q² ) and 7(p² − 4/3q² )​.

To Find:

Divide the given expressions.

Solution:

=  $(\frac{7}{3p^{2} } + 4q^{2}) / 7(p^{2} - \frac{4}{3q^{2} })$.

=  $(\frac{7 + 12 p^{2}q^{2} }{3p^{2} }) / 7(\frac{3p^{2}q^{2}- 4}{3q^{2} } )$.

=  $\frac{7 + 12 p^{2}q^{2}}{7(3p^{2}q^{2}-4 )}$.

=  $\frac{7 + 12 p^{2}q^{2}}{21p^{2}q^{2}-28}$.

Hence, the answer is $\frac{7 + 12 p^{2}q^{2}}{21p^{2}q^{2}-28}$.