7+3V5
28) Find values of values of a and b, if 7+3underroot 5/3 + underroot 5 —(minus) 7-3 underroot 5/3 - underroot 5 = a + underroot 5 b
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Answers
Answered by
4
Answer:
Step-by-step explanation:
Answered by
3
Step-by-step explanation:
First take a^2= 28 - 10*3^(1/2)
=> 5^2 + (- 3^1/2) ^2+ 2 . 5.(-3^1/2) {{ of form x^2 + y^2 + 2.x.y = (x+y)^2}}
=> (5 - 3^(1/2)) ^2
That gives a = 5 - 3^1/2
Now let b^2 = 1/(7 + 4.3^1/2)
Multiply by 7 - 4.3^1/2 on both numerator and denominator
gives, b^2 = 7 - 4.3^1/2
=> (2)^2 + (-3^1/2)^2 + 2.(2).(-3^1/2)
{{ of form x^2 + y^2 + 2.x.y = (x+y)^2}}So this gives
b = 2 - 3^1/2
You asked the value of a- b = 5 - 2 = 3
Thx
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