Question

7(3x-4y)2-28(2x-y)2 ?​

Answer 1

Answer:

$7(3x - 4y)2 - 28(2x - y)2$

$7(3x - 4y)2 = 28(2x - y)2$

$(3x - 4y) = 4(2x - y)$

$3x - 4y = 8x - 4y$

$3x - 8x = 4y - 4y$

$- 5x = 0$

$x = 0$