Question

7(3x-4y)^2-28(2x-y)^2

Answer 1

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Here's your answer...

7(3x-4y)² - 28(2x-y)²
= 7[9x²+16y²-24xy - 4(4x²+y²-4xy)]
= 7[9x²+16y²-24xy-16x²-4y²+16xy]
= 7(-7x²+12y²-8xy)
= -49x²+84y²-56xy

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Answer 2

Answer:

-49x²+84y²-56xy

Step-by-step explanation:

hi guys so I am subhransu Dey.

7(3x-4y)² - 28(2x-y)²

= 7[9x²+16y²-24xy - 4(4x²+y²-4xy)]

= 7[9x²+16y²-24xy-16x²-4y²+16xy]

= 7(-7x²+12y²-8xy)

= -49x²+84y²-56xy

pls mark as brainliest