√(7+4√3)-√(4+2√3)=01
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V(7+4v3)=v(7+2v12)=2+v3
4+2v3=1+v3
(2+v3)-(1+v3)=2-1=1
4+2v3=1+v3
(2+v3)-(1+v3)=2-1=1
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