CBSE BOARD X, asked by surendrakumarsahu216, 5 hours ago

√7/4*3/√7=?
solve the above question..​

Answers

Answered by stu8063bhavya
0

Answer:

sorry I don't know the answer

Answered by rishithrap
0

Answer:

2.67 is the value of 4 \sqrt{28} \div 3 \sqrt{7}4

28

÷3

7

To find:

The value of 4 \sqrt{28} \div 3 \sqrt{7}4

28

÷3

7

Solution:

We have to find the value of 4 \sqrt{28} \div 3 \sqrt{7}4

28

÷3

7

So first we need to expand the values within the square root and then the square numbers can be taken out and then the equation becomes simplified.

=\frac{4 \sqrt{28}}{3 \sqrt{7}}=

3

7

4

28

=\frac{4 \sqrt{4 \times 7}}{3 \sqrt{7}}=

3

7

4

4×7

As we know that the value of,

[Since, the square root value of 4 is 2]

=\frac{4 \times 2 \sqrt{7}}{3 \sqrt{7}}=

3

7

4×2

7

=\frac{8 \sqrt{7}}{3 \sqrt{7}}=

3

7

8

7

\sqrt{7}

7

in the denominator and the numerator place can be cancelled each other.

Therefore,the above equation becomes

=\frac{8}{3}=

3

8

=2.67

Hence the value of 4 \sqrt{28} \div 3 \sqrt{7}4

28

÷3

7

is 2.67.

Similar questions