Question

7.4
Calculate K, for the equilibrium.
Write the expression for the equilibrium constant, K, for each of the fol
reactions:
(i) 2NOC1 (g) + 2NO(g) + Cl, (g)
(ii) 2Cu(NO3), (s) = 2 CuO (s) + 4NO, (g) + O2(g)
(iii) CH,COOC,H,(aq) + H2O(l) = CH COOH (aq) + C,H,OH (aq)
(iv) Fe3+ (aq) + 30H (aq) Fe(OH), (s)
(v) I, (s) + 5F, 2IF
Find out the value of K for each of the following equilibria from the value
(i) 2NOCI (g = 2NO (g) + Cl, (g); K= 1.8 x 10-2 at 500 K

7.5
(iill
CaCO (s) CaOls) + CO (g. K= 167 at 1073 K​

Answer 1

Answer:

(i) 2NOCl (g) 2NO (g) + Cl2 (g) (ii) 2Cu (NO3)2 (s) 2CuO (s) + 4NO2 (g) + O2 (g) (iii) ... for the equilibrium constant, Kc​ for each of the following reactions.

Explanation:

Answer 2

Explanation:

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