Question

{(7^4)p×7^3^p}÷7^5^p=49​

Answer 1

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Answer 2

Answer:

$(( {7}^{4} )p \times {7}^{3p} ) \div {7}^{5p} = 49$

$( {7}^{4p} \times {7}^{3p} ) \div {7}^{5p} = {7}^{2}$

$( {7}^{4p + 3p} )\div {7}^{5p} = {7}^{2}$

${7}^{7p} \div {7}^{5p} = {7}^{2}$

${7}^{7p - 5p} = {7}^{2}$

${7}^{2p} = {7}^{2}$

$same \: bases \: so \: 7 \: will \: get \: off.$

$2p = 2$

$p = \frac{2}{2}$

$p = 1$

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