7
4 ,The sum of father's age and twice the age of his son is 70.If we double
the age of the father and add it to the age of his son the sum is 95.find
their present ages.
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The age of the father is 40 years and the age of his son is 15 years
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Answer:
The age of the father is 40 years and age of the son is 15 years.
Given:
- The sum of father's age and twice the age of his son is 70.
- If we double the age of father and add it to the age of his son the sum is 95.
To find:
- Their present ages.
Solution:
Let the age of the father be x years and y years respectively.
According to the first condition.
⇒ x + 2y = 70...(1)
According to the second condition.
⇒ 2x + y = 95...(2)
From equation (1) we get,
→ x = 70 - 2y
Substitute x = 70 - 2y in equation (2), we get
⇒ 2 (70 - 2y) + y = 95
⇒ 140 - 4y + y = 95
⇒ 3y = 45
⇒ y = 45/3
⇒ y = 15
Substitute y = 15 in equation (1) we get,
⇒ x + 2 (15) = 70
⇒ x = 70 - 30
⇒ x = 40
∴ The father's age is 40 years and age of son is 15 years.
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