Question

7. 40% of the passengers from a bus got down at
station A. 75% of the remaining got down at
station B. If the remaining 12 passengers were
taken to station C, find the original number
of passengers.​

Answer 1

Answer:

Let x be total no. of passengers present initially.

60% of 25% of x = 12

$\frac{60}{100} \times \frac{25}{100} \times x = 12$

x = $\frac{12 \times 100 \times 100}{60 \times 25}$

= 80

There were 80 passengers initially.

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