Question

7= 43+ (n-1) ×-4 pls solve​

Answer 1

Answer:

Given

7=43+(n-1)×4

7=43-4n+4

7-43-4=4n

-40=4nn=-10

Answer 2

Answer:

$7 = 43 + (n - 1) \times - 4 \\ 7 - 43 = (n - 1) \times - 4 \\ - 36 = (n - 1) \times - 4 \\ \frac{ \cancel{ - 36}}{ \cancel{ - 4}} = n - 1 \\ 9 = n - 1 \\ n - 1 = 9 \\ n = 9 + 1 \\ n = 10$

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