7+√48,Find the square roots of following surd.
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In the attachment I have answered
this problem.
The method of finding Square root of
7+4 root(3) is simple.
I have explained it in simple algebraic
steps.
See the attachment for detailed
solution
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Answered by
2
Hi ,
√7 + √48
= √7 + √(2 × 2 × 3 × 4 )
= √ 7 + 2√ ( 3 × 4 )
= √ ( 4 + 3 ) + 2√ ( 3 × 4 )
= √ [ (√4 )² + ( √3 )² + 2 × √4 × √3 ]
= √ [ √4 + √3 ]²
= √4 + √3
= 2 + √3
Therefore b,
√ 7 + √48 = 2 + √3
I hope this helps you.
: )
√7 + √48
= √7 + √(2 × 2 × 3 × 4 )
= √ 7 + 2√ ( 3 × 4 )
= √ ( 4 + 3 ) + 2√ ( 3 × 4 )
= √ [ (√4 )² + ( √3 )² + 2 × √4 × √3 ]
= √ [ √4 + √3 ]²
= √4 + √3
= 2 + √3
Therefore b,
√ 7 + √48 = 2 + √3
I hope this helps you.
: )
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