7-4x/3=y, 2x+3y+1=0
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The given equations are: (7 − 4x)/ 3 = y ⇒ 4x + 3y = 7 ……..(i) and 2x + 3y + 1 = 0 ⇒2x + 3y = -1 ……….(ii) On subtracting (ii) from (i), we get: 2x = 8 ⇒x = 4 On substituting x = 4 in (i), we get: 16x + 3y = 7 ⇒3y = (7 – 16) = -9 ⇒y = -3 Hence, the solution is x = 4 and y = -3.
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