Math, asked by jyotsna999, 8 months ago

7-4x/3 =y ,2x+3y+1=0 find the value of x and y​

Answers

Answered by giriaishik123
0

Answer:

The given equation are

4x+3y=7 ……(1)

2x+3y=-1 ……(2)

subtracted (2)from (1) we get

4x+3y=7

2x+3y=-1

- - +

2x =8

x=8/2

x=4

putting x=4 in (1) we get

4(4)+3y=7

16+3y=7

3y=7-16

3y=-9

y=-9/3

y=-3

hence x=4 and y=-3

Answered by Anonymous
0

Answer:

2x+3y+1=0 ----(2)

7-4x/3=y ----(1)

substitute y's value from (1) to (2)

2x+3(7-4x/3)=0

2x+(7-4x/3) =0/3=0

x+7-4x/3=0/2 =0

x-4x/3=-7

x-4x=(-7)3

x-4x=-21

-3x=-21

x=-21/-3

x=7 ----(3)

add the value of x from (3) to (1)

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