7-4x/3 =y ,2x+3y+1=0 find the value of x and y
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Answer:
The given equation are
4x+3y=7 ……(1)
2x+3y=-1 ……(2)
subtracted (2)from (1) we get
4x+3y=7
2x+3y=-1
- - +
2x =8
x=8/2
x=4
putting x=4 in (1) we get
4(4)+3y=7
16+3y=7
3y=7-16
3y=-9
y=-9/3
y=-3
hence x=4 and y=-3
Answered by
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Answer:
2x+3y+1=0 ----(2)
7-4x/3=y ----(1)
substitute y's value from (1) to (2)
2x+3(7-4x/3)=0
2x+(7-4x/3) =0/3=0
x+7-4x/3=0/2 =0
x-4x/3=-7
x-4x=(-7)3
x-4x=-21
-3x=-21
x=-21/-3
x=7 ----(3)
add the value of x from (3) to (1)
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