Math, asked by gitakusari877, 5 hours ago

7/(4x + 3y) + 4/(4x - 3y) = 5/4​

Answers

Answered by havockarthik30
3

Answer:

7/(4x + 3y) + 4/(4x - 3y) = 5/4

7/(4x + 3y) + 4/(4x - 3y) = 5/47+4 / (4x)^2 - (3y)^2 = 5/4

7/(4x + 3y) + 4/(4x - 3y) = 5/47+4 / (4x)^2 - (3y)^2 = 5/411 / 16x^2 - 9y^2 =5/4

7/(4x + 3y) + 4/(4x - 3y) = 5/47+4 / (4x)^2 - (3y)^2 = 5/411 / 16x^2 - 9y^2 =5/411×4 = 5(16x^2 - 9y^2)

7/(4x + 3y) + 4/(4x - 3y) = 5/47+4 / (4x)^2 - (3y)^2 = 5/411 / 16x^2 - 9y^2 =5/411×4 = 5(16x^2 - 9y^2)44 = 80x^2 -45y^2

80x^2 -45y^2 = 44

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