Math, asked by Amarjeet03, 9 months ago

7/5√3-5√2 denominator will be

Answers

Answered by Anonymous
1

Answer:

 \frac{7}{ 5\sqrt{3}  - 5 \sqrt{2} }  \times  \frac{5 \sqrt{3}  + 5 \sqrt{2} }{5 \sqrt{3}  + 5 \sqrt{2} }  \\  \frac{7(5 \sqrt{3}  + 5 \sqrt{2} )}{(5 \sqrt{3} ) {}^{2}  -  (5 \sqrt{2}) { }^{2}   }  \\  \frac{35 \sqrt{3} + 35 \sqrt{2}  }{25 \times 3 - 25 \times 2  }  \\  \frac{35 \sqrt{3}  + 35 \sqrt{2} }{75 - 50}  \\  \frac{35( \sqrt{3}  +  \sqrt{2}) }{25}  \\  \frac{7( \sqrt{3} +  \sqrt{2}  )}{5}

using rationalization merhod we will find the denominator

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