Question

7/5+3x/2=8/3
$\frac{7}{3} + \frac{3x}{2 } = \frac{8}{3}$
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Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

$\sf \longmapsto \dfrac{7}{3} + \dfrac{3}{2} x = \dfrac{8}{3}$

Taking LCM of 3 & 2

LCM of 3 and 2 is 6

$\sf \longmapsto \dfrac{2(7) + 3(3x)}{6} = \dfrac{8}{3}$

$\sf \longmapsto \dfrac{14 + 9x}{6} = \dfrac{8}{3}$

Now,cross multiply to both sides

$\sf \longmapsto3(14 + 9x) = 8 \times 6$

$\sf \longmapsto42 + 27x = 48$

$\sf \longmapsto27x = 48 - 42 = 6$

$\sf \longmapsto27x = 6$

$\sf \longmapsto \: x = \dfrac{ \cancel{{6}}}{ \cancel{{27} }} = { \bold{ \dfrac{2}{9} }}$

Check:-

$\sf \longmapsto \dfrac{14 + 9x}{6} = \dfrac{8}{3}$

Taking LHS

$\sf \longmapsto \dfrac{1 4 + 9 \times \dfrac{2}{9} }{6}$

$\sf \longmapsto \dfrac{14 + 2}{6}$

$\sf \longmapsto \dfrac{16}{6} = \dfrac{8}{3}$

Therefore,LHS =RHS (verified)