ᴀ ꜱᴩɪɴɴᴇʀ ᴏꜰ ʀᴀᴅɪᴜꜱ 7.5 ᴄᴍ ɪꜱ ᴅɪᴠɪᴅᴇᴅ ɪɴᴛᴏ 6 ᴇqᴜᴀʟ ꜱᴇᴄᴛᴏʀ ꜰɪɴᴅ ᴛʜᴇ ᴀʀᴇᴀ ᴏꜰ ᴇᴀᴄʜ ꜱᴇᴄᴛᴏʀ
Answers
Given :-
- A spinner of radius, r = 7.5 cm which is divided into 6 equal sectors.
To Find :-
- Area of sector.
Solution :-
Since, The 6 sectors are inside the circle, hence the area of one sector is one sixth the area of the circle.
We know,
- Area of circle = πr²
Where, r = radius
⇒ Area = π × 7.5 × 7.5
⇒ Area = 56.25 π cm²
As discussed earlier, the area of each sector is one sixth of the area of circle, so
⇒ Area of sector = 1/6 (Area of circle)
⇒ Area of sector = 1/6 × 56.25 × π
⇒ Area of sector = 9.375 × π
Put π = 3.14, we get
⇒ Area of sector = 29.4375 or ≈ 29 cm²
Therefore, Area of each sector is 29.4375 cm² or approximately ≈ 29 cm².
Some Information :-
- Area of sector of a circle of radius r which subtends an angle θ at the centre is given by:
⇒ Area = πr² θ/360
Step-by-step explanation:
Given :-
A spinner of radius, r = 7.5 cm which is divided into 6 equal sectors.
To Find :-
Area of sector.
Solution :-
Since, The 6 sectors are inside the circle, hence the area of one sector is one sixth the area of the circle.
We know,
Area of circle = πr²
Where, r = radius
⇒ Area = π × 7.5 × 7.5
⇒ Area = 56.25 π cm²
As discussed earlier, the area of each sector is one sixth of the area of circle, so
⇒ Area of sector = 1/6 (Area of circle)
⇒ Area of sector = 1/6 × 56.25 × π
⇒ Area of sector = 9.375 × π
Put π = 3.14, we get
⇒ Area of sector = 29.4375 or ≈ 29 cm²
Therefore, Area of each sector is 29.4375 cm² or approximately ≈ 29 cm².
Some Information :-
Area of sector of a circle of radius r which subtends an angle θ at the centre is given by:
⇒ Area = πr² θ/360