Question

ᴀ ꜱᴩɪɴɴᴇʀ ᴏꜰ ʀᴀᴅɪᴜꜱ 7.5 ᴄᴍ ɪꜱ ᴅɪᴠɪᴅᴇᴅ ɪɴᴛᴏ 6 ᴇqᴜᴀʟ ꜱᴇᴄᴛᴏʀ ꜰɪɴᴅ ᴛʜᴇ ᴀʀᴇᴀ ᴏꜰ ᴇᴀᴄʜ ꜱᴇᴄᴛᴏʀ​

Answer 1

Given :-

• A spinner of radius, r = 7.5 cm which is divided into 6 equal sectors.

To Find :-

• Area of sector.

Solution :-

Since, The 6 sectors are inside the circle, hence the area of one sector is one sixth the area of the circle.

We know,

• Area of circle = πr²

Where, r = radius

⇒ Area = π × 7.5 × 7.5

⇒ Area = 56.25 π cm²

As discussed earlier, the area of each sector is one sixth of the area of circle, so

⇒ Area of sector = 1/6 (Area of circle)

⇒ Area of sector = 1/6 × 56.25 × π

⇒ Area of sector = 9.375 × π

Put π = 3.14, we get

⇒ Area of sector = 29.4375 or ≈ 29 cm²

Therefore, Area of each sector is 29.4375 cm² or approximately ≈ 29 cm².

Some Information :-

• Area of sector of a circle of radius r which subtends an angle θ at the centre is given by:

⇒ Area = πr² θ/360

Answer 2

Step-by-step explanation:

Given :-

A spinner of radius, r = 7.5 cm which is divided into 6 equal sectors.

To Find :-

Area of sector.

Solution :-

Since, The 6 sectors are inside the circle, hence the area of one sector is one sixth the area of the circle.

We know,

Area of circle = πr²

Where, r = radius

⇒ Area = π × 7.5 × 7.5

⇒ Area = 56.25 π cm²

As discussed earlier, the area of each sector is one sixth of the area of circle, so

⇒ Area of sector = 1/6 (Area of circle)

⇒ Area of sector = 1/6 × 56.25 × π

⇒ Area of sector = 9.375 × π

Put π = 3.14, we get

⇒ Area of sector = 29.4375 or ≈ 29 cm²

Therefore, Area of each sector is 29.4375 cm² or approximately ≈ 29 cm².

Some Information :-

Area of sector of a circle of radius r which subtends an angle θ at the centre is given by:

⇒ Area = πr² θ/360

hope this helps you!!

thank you ⭐