Question

7+√5/7-√5 ...solve it....​

Answer 1

7+√5/7-√5

=(7+√5)×(7+√5)/(7-√5)×(7+√5)

= (49+14√5+5)/(7-5)

=(54+14√5)/2

=2(27+7√5)/2

=27+7√5

Answer 2

Answer:

$\frac{7 + \sqrt{5} }{7 - \sqrt{5} } \\ \\ \frac{7 + \sqrt{5} }{7 - \sqrt{5} } \times \frac{7 + \sqrt{5} }{7 + \sqrt{5} } \\ \\ \frac{(7 + \sqrt{5}) {}^{2} }{(7) {}^{2} - (\sqrt{5}) {}^{2} } \\ \\ \frac{49 + 5 + 14 \sqrt{5} }{49 - 5} \\ \\ \frac{54 + 14 \sqrt{5} }{44} \\ \\ \frac{2(27 + 7 \sqrt{5}) }{44} \\ \\ \frac{27 + 7 \sqrt{5} }{22}$

Hope it helps!!!