Question

. 7.5 g of a gas occupies a volume of 5.6 litres at 0o C and 1 atm pressure. The gas is

Answer 1

Answer:

Given conditions⇒

∵ 5.6 litres of the gas at S.T.P. weighs 7.5 grams.

∴ 1 litres of the gas at S.T.P. weighs 7.5/5.6 grams.

∴ 22.4 litres of the gas at S.T.P. weighs 7.5/5.6 × 22.4 = 30 g.

22.4 litres of the gas at S.T.P. weighs equals to its molar mass.

∴ Molar mass of the gas = 30 g/mole.

For finding the name of the compounds in the given option, Let us first find the molar mass of the compounds.  

Molar mass of the NO = 14 + 16 = 30 g/mole.

Molar mass of the N₂O = 28 + 16 = 44 g/mole.

Molar mass of the O = 14 + 16 = 30 g/mole.

Molar mass of the CO₂ = 14 + 16 × 2 = 44 g/mole.

From this we can see that NO is the correct answer.