7.5=n1 x 27 + n2 x 24
0.35=1.5 x n1 + n2
how do i get n1 and n2
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Answer:
7.5=n1×27+n2×24_(1)
0.35=1.5×n1+n2_(2)
By using substitution method,
from (2),
0.35-1.5×n1=n2_(3)
put euation (3) in equation (1) ,we get
7.5=n1×27+(0.35-1.5×n1)×24
=>7.5=n1×27+8.40-36.0×n1
=>7.5=n1×27-36.0×n1+8.40
=>7.50-8.40=n1×27.0-36.0×n1
=> -0.9= -9×n1
=> -0.9/-9= n1
=> 0.1=n1
Now, put the value of n1 in equation (3) to find the value of n2,
0.35-1.5×0.1=n2
=>0.35-0.15=n2
=>0.2=n2
Therefore, n1 = 0.1 and n2=0.2
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