Math, asked by andyrahme1234, 4 months ago

7.5=n1 x 27 + n2 x 24
0.35=1.5 x n1 + n2
how do i get n1 and n2

Answers

Answered by Anonymous
2

Answer:

7.5=n1×27+n2×24_(1)

0.35=1.5×n1+n2_(2)

By using substitution method,

from (2),

0.35-1.5×n1=n2_(3)

put euation (3) in equation (1) ,we get

7.5=n1×27+(0.35-1.5×n1)×24

=>7.5=n1×27+8.40-36.0×n1

=>7.5=n1×27-36.0×n1+8.40

=>7.50-8.40=n1×27.0-36.0×n1

=> -0.9= -9×n1

=> -0.9/-9= n1

=> 0.1=n1

Now, put the value of n1 in equation (3) to find the value of n2,

0.35-1.5×0.1=n2

=>0.35-0.15=n2

=>0.2=n2

Therefore, n1 = 0.1 and n2=0.2

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