Question

7× 5 under root prove that it is irrational ​

Answer 1

To prove 7√5 as irrational number.

let 7√5 as rational number.

so it can be written in p/q form.(q is not equal to 0)

where p and q are integers and co primes.

7√5 = p/q

√5 = p/7q

here p, q and 7 are any integers so they will rational number.

but it contradict the fact that√5 is an irrational number.

so our hypothesis was wrong.

7√5 is irrational number.

hence proved.