Math, asked by ShivshankarLayak, 6 months ago

(7) 5% वार्षिक दर से बढ़ते हुए वर्ष 2000 के अंत में एक स्थान की जनसंख्या 20,000 हो
गई। निम्नलिखित को ज्ञात कीजिए।
(i) वर्ष 1998 में जनसंख्या (ii) वर्ष 2002 में जनसंख्या।​

Answers

Answered by bhagyashreechowdhury
4

Given:

5% वार्षिक दर से बढ़ते हुए वर्ष 2000 के अंत में एक स्थान की जनसंख्या 20,000 हो

गई।

To find:

निम्नलिखित को ज्ञात कीजिए।

वर्ष 1998 में जनसंख्या

वर्ष 2002 में जनसंख्या।​

Solution:

The population of the year 2000 = 20,000

The rate of increase in population = 5%

We know,

\boxed{\bold{A = P [1 + \frac{R}{100} ]^n}}

where A = population after n years, P = initial population, R = rate of increase and n = no. of years

Finding the population in the year 1998:

The no. of years (1998 to 2000), n = 2 years

Therefore,

A_2_0_0_0 = P_1_9_9_8 [1 + \frac{R}{100} ]^n

\implies 20000 = P [1 + \frac{5}{100} ]^2

\implies 20000 = P [ \frac{105}{100} ]^2

\implies P = 20000 [ \frac{100}{105} ]^2

\implies \bold{P = 18141} (approximately)

Thus, the population in the year 1998 was → 18141.

Finding the population in the year 2002:

The no. of years (2000 to 2002), n = 2 years

Therefore,

A_2_0_0_2 = P_2_0_0_0 [1 + \frac{R}{100} ]^n

\implies A = 20000 [1 + \frac{5}{100} ]^2

\implies A = 20000 \times [ \frac{105}{100} ]^2

\implies \bold{A = 22050}

Thus, the population in the year 2002 is → 22050.

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