Math, asked by Lightt9914, 8 months ago

(7+5root2)^1/3 + (7-5root2)^1/3 is

Answers

Answered by fab13
0

Answer:

(7 + 5 \sqrt{2} ) {}^{ \frac{1}{3} }  + (7 - 5 \sqrt{2} ) {}^{ \frac{1}{3} }  \\  =  \sqrt[3]{((7 + 5 \sqrt{2}) {}^{ \frac{1}{3} } + (7 - 5 \sqrt{2} ) {}^{ \frac{1}{3} }) {}^{3}    } \\  =   \sqrt[3]{7 + 5 \sqrt{2}  + 7 - 5 \sqrt{2} + 3(7 + 5 \sqrt{2} )(7 - 5 \sqrt{2} )(7 + 5 \sqrt{2} + 7 - 5 \sqrt{2}  )} \\  =  \sqrt[3]{14 + 3( {7}^{2} - (5 \sqrt{2} ) {}^{2} ) \times 14 }  \\  =  \sqrt[3]{14 + 42(49 - 50)}  \\  =  \sqrt[3]{14 + 42 \times ( - 1)}  \\  =  \sqrt[3]{14 - 42}  \\  =  \sqrt[3]{ - 28}  \\  =  - 3.0365....

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