Question

(-7,6),(2,-2),(8,5) find the centroid of the triangle whose vertices are given below

Answer 1

Centroid = (x1+x2+x3)/ 3, (y1+y2+y3)/3 = (-7+2+8)/3 , (6-2+5)/3 = 3/3 , 9/3 = 1,3

So, centroid  = (1,3)

Where x,y denote the given points

Answer 2

Answer:

Centroid = (1,3)

Step-by-step explanation:

As per the question,

let,

P = (x₁,y₁) = (-7,6)

Q = (x₂,y₂) = (2,-2)

R = (x₃,y₃) = (8,5)

Formula used for centroid of the triangle whose vertices are P, Q and R, is given by:

$C = (\frac{x_{1}+x_{2}+x_{3}}{3}), (\frac{y_{1}+y_{2}+y_{3}}{3})$

Now,

Put the values, we get

$C = (\frac{-7+2+8}{3}), (\frac{6+(-2)+5}{3})$

$C = (\frac{3}{3}), (\frac{9}{3})$

$C = (1,3)$

Hence, the centroid of the triangle whose vertices are given = (1,3).