Question

7.6) (ii) You have a cylinder of argon gas at 19.8 atm pressure at 19°C. The volume of argon in the cylinder is 50.0 L. What would be the volume of this gas if you allowed it to expand to the pressure of the surrounding air (0.974 atm)? Assume the temperature remains constant.​

Answer 1

Answer:

The volume of argon gas at 0.974 atm is 1016.43L.

Explanation:

Given,

    Initial Pressure, P₁ = 19.8atm

      Initial volume, V₁ = 50L

    Final Pressure, P₂ = 0.974atm

          Temperature = 19°C

Since Temperature is constant we can apply Boyle's law,

              P₁V₁ = P₂V₂

Rearranging the equation,

⇒               V₂ = P₁V₁ /  P₂

Substituting the values of P₁, V₁, and P₂

⇒           V₂ = 19.8×50L/ 0.974 = 1016.43L

Hence, the volume of gas is 1016.43L.