Question

7⬜7 ⬜0 ⬜7⬜7=8

CAN YOU MAKE THIS EQUATION CORRECT BY USING THREE OF THESE FOUR SYMBOLS? × ÷ + -


pls help me this is emergency​

Answer 1

Step-by-step explanation:

7x7-0+7÷7=8

7x7=49

49-0=49

49+7=56

56÷7=8

Answer 2

Answer:

The value of \angle Q∠Q is 7070 °.

Step-by-step explanation:

Given in \triangle PQR△PQR side QRQR is produced to SS such that \angle PSR=140∠PSR=140 °.

Also given \angle P = \angle Q∠P=∠Q .

The angles created between the side of the polygon and the extended adjacent side of the polygon are known as exterior angles. According to the external angle theorem, when a triangle’s side is stretched, the resulting exterior angle is equal to the sum of the measurements of the triangle’s two opposed internal angles.

Here \angle PSR∠PSR is the exterior angle.

The opposed internal angles are P,QP,Q .

From the definition,

\angle P +\angle Q=\angle PSR∠P+∠Q=∠PSR

\angle Q +\angle Q = 140∠Q+∠Q=140

2\angle Q =1402∠Q=140

\angle Q=70∠Q=70 .

Therefore, the required angle is \angle Q=70∠Q=70 °.