Question

(7×7)^3÷(49×7)^3×(2401)^2=7^?​

Answer 1

ANS ]

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$({7 \times 7})^{3} \div ({49 \times 7})^{3} \\ \times ( {2407})^{2} = {7}^{?}$

$\frac{49 \times 49 \times 49}{343 \times 343 \times 343} \times ( {2401})^{2} = {7}^{?}$

$\frac{1}{7 \times 7 \times 7 } \times ({2401})^{2} = {7}^{?}$

$\frac{1}{343} \times 5764801 = {7}^{?}$

$16803 = {7}^{?}$

$? = 5$

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