Math, asked by 919087352449, 2 days ago

7 7 7. + The equation, whose roots are the squares of the roots of r' + pr? +8+r=0 is A) Y +r? (22- p?)+x(q? - 2 pr)+r? = 0 B) x+x? (29-p?) + x[q? -2pr)->? = 0 C)Y+r (29+ p')=xq+2 pr)-++ =0 D) x +7 (2q + p?)+x(q? –2 pr)--? =0 o a​

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Answered by kanwarrukman531
1

Answer:

y63s6p21yzwf653a7s58ez8 d04uwoco6oxiry0w54oy3a0wi6oez5i 4so5but pxtj3z9w4dkyzegke

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