7+77+777........nth term
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It was of 11th class que.
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Answer:
7/9 [ 10/9 ( 10ⁿ - 1 ) ] - n
Step-by-step explanation:
7 + 77 + 777 + .... n terms
Taking common term we get,
⇒ 7 ( 1 + 11 + 111 + ... n terms )
Multiplying and dividing by 9 we get,
⇒ 7 / 9 × 9 ( 1 + 11 + 111 + ... n terms )
⇒ 7 / 9 ( 9 + 99 + 999 + ... n terms )
9 can be written as 10 - 1.
99 can be written as 100 - 1
999 can be written as 1000 - 1
Similarly all can be written in the form 10ⁿ⁻¹ - 1
So we can write it as:
⇒ 7/9 ( 10 - 1 + 100 - 1 + 1000 - 1 + .... 10ⁿ⁻¹ - 1 )
⇒ 7/9 ( 10 + 100 + 1000 + ... 10ⁿ⁻¹ ) - 1 ( 1 + 1 + 1 ... n terms )
⇒ 7/9 [ 10/10-1 ( 10ⁿ - 1 ) ] - n
⇒ 7/9 [ 10/9 ( 10ⁿ - 1 ) ] - n
This is the required answer.
Hope it helped !!
Thanks !!
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