7(7th term of ap)=11(11 th term of ap) then 18th term of ap is
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a + 6d = 11
a = 11 - 6d --- (i)
a + 10d = 18
a = 18 - 10d --- (ii)
Now we compare both equations:
Since we know that both the values stand for 'a', we can say that they are equal to each other.
11 - 6d = 18 - 10d
11 - 18 = -10d + 6d
-7 = -4d
7/4 = d
1.75 = d
Now we find the value of 'a' by substituting the value of 'd' in equation (i):
a = 11 - 6d
= 11 - 6(1.75)
= 11 - 10.5
= 1.5
First term of AP = 1.5
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