Question

(7/8)^-3 × (9/5)^0 × (8)^-2 × (1/7)^-1​

Answer 1

Axioms and laws used :-

n^0 = 1

n^-1 = (1/n) [resiprocal of n]

Solution :-

(7/8)^-3 × (9/5)^0 × (8)^-2 × (1/7)^-1

= (8/7)^3 x 1 x (1/8)^2 x (7)

= (512/343) x (1/64) x 7

= (8/49) ans