Question

7/8
8/7
-7/8
-8/7
3.Find the value of x of the following expression (2/3)⁻⁵ x (2/3)⁻¹¹ = (2/3)⁸ˣ​

Answer 1

Step-by-step explanation:

$({ \frac{2}{3} })^{ - 11} \times ( { \frac{2}{3} })^{ - 5} = ({ \frac{2}{3} }) ^{8x} \\ \\ = > - 11 - 5 = 8x \\ \\ = > - 16 = 8x \\ \\ = > x = \frac{ - 16}{8} = - 2$

Answer 2

Answer:

Value of x is -15/8

Step-by-step explanation:

Given,

⇒ $[\frac{2}{3}] ^{2}$ x $[\frac{2}{3}] ^{-11} = [\frac{2}{3}] ^{8x}$

We need,

⇒ Value of x

According to the identity ,

⇒ $a^{m}$ x $a^{n} = a^{(m+n)}$

So when the formula is applied here...

⇒ $\frac{2}{3} ^{[-5+(-11)]} = \frac{2}{3} ^{(8x)}$

As bases are same Powers can be equated, So

→ $[-5+(-11)] = 8x$

→ $[-5-11] = 8x$

→ $-15 = 8x$

→ $\frac{-15}{8} = x$

→ $X=\frac{-15}{8}$

So Value of x is -15/8