Question

7+8+9+10+..........+56= ?
plz solve it​

Answer 1

Step-by-step explanation:

$7 + 8 + 9 + 10 + ........ + 56$

Here , The given series is in A.P. in which first term is 7 and common difference is 1 and nth term is 56

Therefore, first find n by using the formula

$nth \: term \: = a + (n - 1)d \\ = > 56 = 7 + (n - 1) \\ = > 49 = n - 1 \\ = > 50 = n$

Now the required sum is

$\frac{n}{2}(first \: term \: + last \: term) \\ = \frac{50}{2} (7 + 56) \\ = 25 \times 63 \\ = 1575$

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Answer 2

Answer:

5436

Step-by-step explanation:

the answer is 5436