Question

7,9,11...... Find the sum of first 10th term.

Answer 1

Heya !!!


AP = 7 , 9 , 11


Here,


First term (A) = 7



Common Difference (D) = 9-7 = 2



Sn = N/2 × [ 2A + ( N -1) × D ]




S10 = 10/2 × [ 2 × 7 + ( 10-1) × 2 ]





=> 5 ( 14 + 18)



=> 5 ( 32)



=> 160




★ HOPE IT WILL HELP YOU ★

Answer 2

Hi

This is your answer.

First term = 7
Common difference = 2

Sum of First 10 terms = n/2[2a +(n-1)d]

= 10/2[2×7 + (10-1)2]
= 5[14+18]
= 5×32
=160

Hence the sum of first 10 terms of this AP is 160.