7/9-12/45 what is answer
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Step-by-step explanation:
We Know that,
\begin{gathered}\large \bf \red\bigstar \: \: \orange{ \underbrace{ \underline{sec A = \frac{1}{cosA} }}} \\ \end{gathered}
★
sec A=
cosA
1
Hence,
\begin{gathered}:\longmapsto \rm secA = \frac{1}{8/17} \\ \end{gathered}
:⟼secA=
8/17
1
\begin{gathered}\purple{ \large :\longmapsto \underline {\boxed{{\bf sinA = \frac{17}{8} } }}} \\ \end{gathered}
:⟼
sinA=
8
17
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