Question

(7/9)-¹²×(9/7)-¹⁰

find answer ​

Answer 1

$\large \underline{ \red{ \boxed{ \bf \orange{Your\: answer}}}}$

Thanks❤️

Answer 2

Answer:

 $(\frac{7}{9})^{12}*(\frac{9}{7})^{10}$ = $\frac{49}{81}$

Step-by-step explanation:

Given : The given expression is $(\frac{7}{9})^{12}*(\frac{9}{7})^{10}$.$7^{12-10} *\frac{1}{9^{12-10}}$

To find : The value of given expression.

Solution :

• The given expression is $(\frac{7}{9})^{12}*(\frac{9}{7})^{10}$.
• We have to find the value of given expression.
• So,

      $(\frac{7}{9})^{12}*(\frac{9}{7})^{10}$ = $\frac{7^{12} }{9^{12} } *\frac{9^{10}}{7^{10}}$    (∵ $(\frac{a}{b})^{m} =\frac{a^{m} }{b^{n} }$)

• Now, we can rewrite this expression as,

                 = $\frac{7^{12}}{7^{10}} *\frac{9^{10}}{9^{12}}$

• Use $\frac{a^{m}}{a^{n} }=a^{m-n}$, we get

                 = $7^{12-10} *\frac{1}{9^{12-10}}$

                 = $7^{2}*\frac{1}{9^{2}}$

                 $= \frac{7^{2}}{9^{2} }$

                 = $\frac{49}{81}$

• ∴  $(\frac{7}{9})^{12}*(\frac{9}{7})^{10}$ = $\frac{49}{81}$