Question

7,9,(30),4,5; 17,8,(50),6,3; 10,21,(?)6,3

Answer 1

32 is the answer. according to the pattern there is adding two

Answer 2

The number is 62

Given:

7,9,(30),4,5; 17,8,(50),6,3; 10,21,(?)6, 3

To find:

The missing number in the series

Solution:

(i) For the first set $\Rightarrow$ 7, 9, (30), 4, 5  

Step I: Adding all 4 numbers $\Rightarrow$ 7+9+4+5 = 25

Step II: Sum $\times 2 \Rightarrow 25 \times$ 2=50

Step III: 50 – Product of last 2 number $\Rightarrow 50-(4 \times 5)$=50-20=30  

Thus, desired number is 30.  

(ii) For the second set$\Rightarrow  17, 8, (50), 6, 3$

Step I: Adding all 4 numbers$\Rightarrow 17+8+6+3 = 34$

Step II: Sum $\times 2 \Rightarrow 34 \times 2=68$

Step III: 68 – Product of last 2 number$\Rightarrow 68-(6 \times 3)=68-18=50$

Thus, desired number is 50.  

(iii) For the third set $\Rightarrow  10, 21, (?), 6, 3$

Step I: Adding all 4 numbers $\Rightarrow 10+ 21+ 6+3 = 40$

Step II: Sum $\times 2 \Rightarrow 40 \times 2=80$

Step III: 80 – Product of last 2 number $\Rightarrow 80-(6 \times 3)=80-18=62$

Thus, desired number is 62.