Question

7. A 3 phase 50 Hz, star connected 2000KVA , 2300v alternator has effective resistance of 0.12 and gives a short circuit current of 600A certain field exitation with the same exitation, the open circuit voltage was 900 calculate i the synchronous impedance and reactance (ü) the full load regulation when the powey factor is 0.8 lagging iii) the full load regulation when the power factor is 0.6 leading​

Answer 1

4 A 3-phase 50-Hz star-connected 2000-kVA, 2,300 V alternator gives a short-circuit current of 600 A for a certain field excitation. With the same excitation, the open circuit voltage was 900 V. The resistance between a pair of terminals was 0.12 Q. Find full-load regulation at 0.8 p.f. lagging. Assume effective armature resistance is 1.5 times the armature resistance due to skin effect

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