Question

7. A 4 m long rod of negligible weight is supported at
a point 125 cm from its one end and a load of
18 kgf is suspended at a point 60 cm from the
support on the shorter arm.​

Answer 1

Answer:

Total length of rod= 4m= 400 cm

a) 18kgf load is placed at 60 cm from the support.

W Kgf is placed at 250 cm from the support.

By the principle of moments,

18 × 60 = W × 250

W= 43.2 kgf

b) Given W= 5 kgf

18kgf load is placed at 60 cm from the support.

Let 5 kgf of weight is placed at d cm from the support.

By the principle of moments,

18 × 60 = 5 × d

d= 216 cm from the support on the longer arm.

c) It belongs to class I lever.

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