Question

7. A 8000 kg engine pulls a train of 5 wagons, each of 2000 kg,
along a horizontal track. If the engine exerts a force of 40000 N
and the track offers a friction force of 5000 N, then calculate:
(a) the net accelerating force and
(b) the acceleration of the train.



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Answer 1

To Find:-

a) Net accelerating force

b) Acceleration of the train

Given:-

Mass of Engine = 8000kg

Mass of 1 wagon = 2000kg

Mass of 5 wagon= 2000×5=10000kg

Engine exerts a force of 40000N

Track returns force of 5000N

Solution:-

a)

Net accelerating force

= 40000-5000=35000N

therefore the net Accelerating force is 35000 N

b)

Acceleration of the train

8000 kg for engine

+

10000 kg for all wagons

that is

18000kg

Total Net accelerating force= 35000N

we know

Force=Mass×Acceleration

Acceleration=Force÷Mass

a=35000÷18000

a=35÷18

a=1.94

Therefore the acceleration is 1.94m/s²

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Answer 2

Answer:

Fnet​=F−friction

    =40000−5000

    =35000 N

Step-by-step explanation:

Answer:

Given parameters

Mass of the engine (M) = 8000 kg

Number of wagons = 5

Mass of the wagons (m) = 2000 kg

Force exerted by the engine (F ) = 40000 N

Frictional force offered by the track (Ff) = 5000 N

(a) Net force (Fa) = F – Ff

Fa = 40000 N – 5000 N

Fa = 35000 N

(b) Let us consider the acceleration of the train to be a m/s2

Acceleration is the ratio of net acceleration force by mass, i.e.

a = Fa/m