Question

7) a) A car travels a distance of 10mt starting from rest with
velocity 4m/s, find its acceleration ?​

Answer 1

u=0m/s(at rest)
v=4 m/s
s=10 m
a=?
2as=v^2-u^2
2a(10)= (4)^2-(0)^2
20a=16
a=16/20
a=4/5
a=4.25 m/s^2

Answer 2

To Find:-

• Find the acceleration of the car.

Given:-

• A car travels a distance of 10m .
• It starts from rest and gains a velocity of 4 m/s.

Solution:-

As we know that:-

$\tt\implies \: { v }^{ 2 } - { u }^{ 2 } = 2as$

Substituting Values:-

$\tt\implies \: { 4 }^{ 2 } - { 0 }^{ 2 } = 2( a )( 10 )$

$\tt\implies \: 16 = 20a$

$\tt\implies \: a = \cancel\dfrac { 16 } { 20 }$

$\tt\implies \: a = \dfrac { 4 } { 5 }$

$\tt\implies \: a = 0.8 \: m/ { s }^{ 2 }$