Question

7. a and B are zeroes of the quadratic polynomial x2 - 6x + y. Find the value of 'y' if
3a + 2B = 20.​

Answer 1

Answer:

Let, f(x) = x² – 6x + y

From the given,

3α + 2β = 20———————(i)

From f(x),

α + β = 6———————(ii)

And,

αβ = y———————(iii)

Multiply equation (ii) by 2. Then, subtract the whole equation from equation (i),

=> α = 20 – 12 = 8

Now, substitute this value in equation (ii),

=> β = 6 – 8 = -2

put the value of α and β in equation (iii) to get the value of y, such as;

y = αβ = (8)(-2) = -16

Step-by-step explanation:

Answer 2

❥︎ Answer࿐

given -

a and B are two zeroes

3a+2B=20 let equation -(1)

To find -

value of Y

solution

as we know

a+B= -b/a

a+B= -(-6)/1

a+B=6 equation (2)

and aB=c/a

aB=y/1. equation (3)

on solving equation (1) and (2)

3a+2B= 20

a+B=6

a=8

$\huge \underline \frak \pink {value- of -a=8}$

and put value of a in equation (2)

a+B=6

8+B=6

8-6=-B

B= -2

$\huge \underline \frak \pink {value -of -B is =-2}$

now put value of a and B in equation (3)

aB=y

8*(-2)=y

-16=y

hence ,the value of y is

$\huge \underline \frak \pink {-16}$

$\huge\tt\underline\blue{Thanks}$

$\huge \underline \frak \pink {Hope-its-helpful}$

l

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