Question

7. a? - b? + 2bc - c?​

Answer 1

Answer:

⇒a

2

−b

2

−c

2

+2bc+a+b−c

⇒(a

2

−(b

2

+c

2

−2bc))+(a+b−c)

∵(x−y)

2

=x

2

−2xy+y

2

So⇒(a

2

−(b−c)

2

)+(a+b−c)

⇒(a+b−c)(a−b+c)+(a+b−c)

⇒(a+b−c)(a−b+c+1)

Step-by-step explanation:

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Answer 2

Answer:

a? - b? + 2bc - c?=a²-b²+2bc - c²

Step-by-step explanation:

a²-b²+2bc-c² =a² - (b² -2bc +c²)

=a² - (b-c)²

=(a-(b-c))(a+(b-c)) [ using identity a²-b² =(a-b)(a+b) ]

= (a-b+c)(a+b-c)

hence.,a²-b²+2bc - c² = (a-b+c)(a+b-c)

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