Question

7.A bag contains 16 balls among which 9 are yellow and remaining 7 are green. 3 are drawn on the basis of probability. Find the probability of getting
a. all are yellow
b. 2 are green and a yellow
c. no yellow ball
d. a green and 2 yellow ball​

Answer 1

Step-by-step explanation:

A bag contains 6 red balls, 8 white balls, 5 green balls and 2 black balls. One ball is drawn at random from the bag.

Then total number of balls in bag =6+8+5+2+1=22

Total number of out come =22

(i)The event is getting a White ball=number of white ball in bag=8

Then probability= 22

8 = 11 4

(ii)The event getting the Red or black=The number of red & black ball in bag=6+8+1=9 (one ball is random)

The probability=

22

A bag contains 6 red balls, 8 white balls, 5 green balls and 2 black balls. One ball is drawn at random from the bag.

Then total number of balls in bag =6+8+5+2+1=22

Total number of out come =22

(i)The event is getting a White ball=number of white ball in bag=8

Then probability=

22

8

=

11

4

(ii)The event getting the Red or black=The number of red & black ball in bag=6+8+1=9 (one ball is random)

The probability=

22

9

(iii)The event getting the Not green is total number of ball other then green ball=6+8+2+1=17

The probability=

22

17

(iv) The event getting the Neither white nor black=Total number of balls without white or black ball in bag=6+5=11

The probability=

22

11= 21 9

(iii)The event getting the Not green is total number of ball other then green ball=6+8+2+1=17

The probability=

22

17

(iv) The event getting the Neither white nor black=Total number of balls without white or black ball in bag=6+5=11

The probability=

22 = 21