Math, asked by sauravrai8757, 22 hours ago

7. A bag contains 5 red and 8 green marbles. One marble is drawn from the bag at random. Find the probability that the marble drawn is red.​

Answers

Answered by shivanshipatel982
1

Step-by-step explanation:

Number of red marbles =5

Number of white marbles =8

Number of green marbles =4

Total number of marbles =5+8+4=17

∴ the total number of cases =17

Since there are 4 green marbles, the number of favourable outcomes is 4.

So, P(a green marble) =

Total number of cases

Number of favourable cases

=

17

4

Hence, P(not a green marble) =1−P(a green marble)=1−

17

4

=

17

17−4

=

17

13

please brainlest mark

Answered by nomad30k
2

Step-by-step explanation:

red ball + green marbles = 5+8 = 13

n(s) = 13 as there are total 13 balls

n(a) = 1 as just one ball is to be drawn

thus p(a) = n(a)/n(s)

= 1/13 is probability

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