7. A bag contains 5 red and 8 green marbles. One marble is drawn from the bag at random. Find the probability that the marble drawn is red.
Answers
Answered by
1
Step-by-step explanation:
Number of red marbles =5
Number of white marbles =8
Number of green marbles =4
Total number of marbles =5+8+4=17
∴ the total number of cases =17
Since there are 4 green marbles, the number of favourable outcomes is 4.
So, P(a green marble) =
Total number of cases
Number of favourable cases
=
17
4
Hence, P(not a green marble) =1−P(a green marble)=1−
17
4
=
17
17−4
=
17
13
please brainlest mark
Answered by
2
Step-by-step explanation:
red ball + green marbles = 5+8 = 13
n(s) = 13 as there are total 13 balls
n(a) = 1 as just one ball is to be drawn
thus p(a) = n(a)/n(s)
= 1/13 is probability
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